A definition like:
#define regs_return_value(regs) ((regs)->regs[0])
called with regs_return_value(foo) will be preprocessed to:
((foo)->foo[0])
^^^
So to fix this to ensure the preprocessor compiles such calls correctly.
Signed-off-by: Roel Kluin <roel.kluin@gmail.com>
Signed-off-by: Paul Mundt <lethal@linux-sh.org>
#include <asm/system.h>
#define user_mode(regs) (((regs)->sr & 0x40000000)==0)
-#define user_stack_pointer(regs) ((unsigned long)(regs)->regs[15])
-#define kernel_stack_pointer(regs) ((unsigned long)(regs)->regs[15])
+#define user_stack_pointer(_regs) ((unsigned long)(_regs)->regs[15])
+#define kernel_stack_pointer(_regs) ((unsigned long)(_regs)->regs[15])
#define instruction_pointer(regs) ((unsigned long)(regs)->pc)
extern void show_regs(struct pt_regs *);
#ifdef __KERNEL__
#define MAX_REG_OFFSET offsetof(struct pt_regs, tra)
-#define regs_return_value(regs) ((regs)->regs[0])
+#define regs_return_value(_regs) ((_regs)->regs[0])
#endif /* __KERNEL__ */
#ifdef __KERNEL__
#define MAX_REG_OFFSET offsetof(struct pt_regs, tregs[7])
-#define regs_return_value(regs) ((regs)->regs[3])
+#define regs_return_value(_regs) ((_regs)->regs[3])
#endif /* __KERNEL__ */