lib: objagg: Use struct_size() in kzalloc()
authorGustavo A. R. Silva <gustavo@embeddedor.com>
Wed, 5 Jun 2019 14:45:16 +0000 (09:45 -0500)
committerDavid S. Miller <davem@davemloft.net>
Thu, 6 Jun 2019 02:03:39 +0000 (19:03 -0700)
One of the more common cases of allocation size calculations is finding
the size of a structure that has a zero-sized array at the end, along
with memory for some number of elements for that array. For example:

struct objagg_stats {
...
        struct objagg_obj_stats_info stats_info[];
};

size = sizeof(*objagg_stats) + sizeof(objagg_stats->stats_info[0]) * count;
instance = kzalloc(size, GFP_KERNEL);

Instead of leaving these open-coded and prone to type mistakes, we can
now use the new struct_size() helper:

instance = kzalloc(struct_size(instance, stats_info, count), GFP_KERNEL);

Notice that, in this case, variable alloc_size is not necessary, hence it
is removed.

This code was detected with the help of Coccinelle.

Signed-off-by: Gustavo A. R. Silva <gustavo@embeddedor.com>
Acked-by: Jiri Pirko <jiri@mellanox.com>
Signed-off-by: David S. Miller <davem@davemloft.net>
lib/objagg.c

index 576be22e86de8a2e9b738e91db34b3e4ef295a82..55621fb82e0a327f15e9c0394a9f817a28355ed7 100644 (file)
@@ -605,12 +605,10 @@ const struct objagg_stats *objagg_stats_get(struct objagg *objagg)
 {
        struct objagg_stats *objagg_stats;
        struct objagg_obj *objagg_obj;
-       size_t alloc_size;
        int i;
 
-       alloc_size = sizeof(*objagg_stats) +
-                    sizeof(objagg_stats->stats_info[0]) * objagg->obj_count;
-       objagg_stats = kzalloc(alloc_size, GFP_KERNEL);
+       objagg_stats = kzalloc(struct_size(objagg_stats, stats_info,
+                                          objagg->obj_count), GFP_KERNEL);
        if (!objagg_stats)
                return ERR_PTR(-ENOMEM);