}
/*
- * After doing so, there would be a "hole" in the /proc/iomem when
- * offset is a positive value. It looks like the device return some
- * mmio back to the system, which actually no one could use it.
+ * Since M64 BAR shares segments among all possible 256 PEs,
+ * we have to shift the beginning of PF IOV BAR to make it start from
+ * the segment which belongs to the PE number assigned to the first VF.
+ * This creates a "hole" in the /proc/iomem which could be used for
+ * allocating other resources so we reserve this area below and
+ * release when IOV is released.
*/
for (i = 0; i < PCI_SRIOV_NUM_BARS; i++) {
res = &dev->resource[i + PCI_IOV_RESOURCES];
dev_info(&dev->dev, "VF BAR%d: %pR shifted to %pR (%sabling %d VFs shifted by %d)\n",
i, &res2, res, (offset > 0) ? "En" : "Dis",
num_vfs, offset);
+
+ if (offset < 0) {
+ devm_release_resource(&dev->dev, &pdn->holes[i]);
+ memset(&pdn->holes[i], 0, sizeof(pdn->holes[i]));
+ }
+
pci_update_resource(dev, i + PCI_IOV_RESOURCES);
+
+ if (offset > 0) {
+ pdn->holes[i].start = res2.start;
+ pdn->holes[i].end = res2.start + size * offset - 1;
+ pdn->holes[i].flags = IORESOURCE_BUS;
+ pdn->holes[i].name = "pnv_iov_reserved";
+ devm_request_resource(&dev->dev, res->parent,
+ &pdn->holes[i]);
+ }
}
return 0;
}