<para>
The macro takes an conditional expression to evaluate.
- When <constant>CONFIG_SND_DEBUG</constant>, is set, the
- expression is actually evaluated. If it's non-zero, it shows
- the warning message such as
+ When <constant>CONFIG_SND_DEBUG</constant>, is set, if the
+ expression is non-zero, it shows the warning message such as
<computeroutput>BUG? (xxx)</computeroutput>
- normally followed by stack trace. It returns the evaluated
- value.
- When no <constant>CONFIG_SND_DEBUG</constant> is set, this
- macro always returns zero.
+ normally followed by stack trace.
+
+ In both cases it returns the evaluated value.
</para>
</section>
* snd_BUG_ON - debugging check macro
* @cond: condition to evaluate
*
- * When CONFIG_SND_DEBUG is set, this macro evaluates the given condition,
- * and call WARN() and returns the value if it's non-zero.
- *
- * When CONFIG_SND_DEBUG is not set, this just returns zero, and the given
- * condition is ignored.
- *
- * NOTE: the argument won't be evaluated at all when CONFIG_SND_DEBUG=n.
- * Thus, don't put any statement that influences on the code behavior,
- * such as pre/post increment, to the argument of this macro.
- * If you want to evaluate and give a warning, use standard WARN_ON().
+ * Has the same behavior as WARN_ON when CONFIG_SND_DEBUG is set,
+ * otherwise just evaluates the conditional and returns the value.
*/
-#define snd_BUG_ON(cond) WARN((cond), "BUG? (%s)\n", __stringify(cond))
+#define snd_BUG_ON(cond) WARN_ON((cond))
#else /* !CONFIG_SND_DEBUG */
static inline void _snd_printd(int level, const char *format, ...) {}
#define snd_BUG() do { } while (0)
-static inline int __snd_bug_on(int cond)
-{
- return 0;
-}
-#define snd_BUG_ON(cond) __snd_bug_on(0 && (cond)) /* always false */
+
+#define snd_BUG_ON(condition) ({ \
+ int __ret_warn_on = !!(condition); \
+ unlikely(__ret_warn_on); \
+})
#endif /* CONFIG_SND_DEBUG */