Each pair of DPs only needs to be compared once when searching for
a non-unique prio value.
Signed-off-by: David Ward <david.ward@ll.mit.edu>
Acked-by: Jamal Hadi Salim <jhs@mojatatu.com>
Signed-off-by: David S. Miller <davem@davemloft.net>
if (q == NULL)
continue;
- for (n = 0; n < table->DPs; n++)
- if (table->tab[n] && table->tab[n] != q &&
- table->tab[n]->prio == q->prio)
+ for (n = i + 1; n < table->DPs; n++)
+ if (table->tab[n] && table->tab[n]->prio == q->prio)
return 1;
}