block, bfq: remove the removal of 'next' rq in bfq_requests_merged

Since bfq_finish_request() is always called on the request 'next',
after bfq_requests_merged() is finished, and bfq_finish_request()
removes 'next' from its bfq_queue if needed, it isn't necessary to do
such a removal in advance in bfq_merged_requests().

This commit removes such a useless 'next' removal.

Signed-off-by: Filippo Muzzini <filippo.muzzini@outlook.it>
Signed-off-by: Paolo Valente <paolo.valente@linaro.org>
Signed-off-by: Jens Axboe <axboe@kernel.dk>

diff --git a/block/bfq-iosched.c b/block/bfq-iosched.c
index aa32e56cb3850145bed5c53b326d31724db176dc..dd527bab57c2a593ac7e6b53a8dc0ab4c528c11d 100644 (file)
--- a/block/bfq-iosched.c
+++ b/block/bfq-iosched.c
@@ -1845,8 +1845,6 @@ static void bfq_request_merged(struct request_queue *q, struct request *req,
  * exploits this hook to address the following issue: if 'next' has a
  * fifo_time lower that rq, then the fifo_time of rq must be set to
  * the value of 'next', to not forget the greater age of 'next'.
- * Moreover 'next' may be in a bfq_queue, in this case it must be
- * removed.
  *
  * NOTE: in this function we assume that rq is in a bfq_queue, basing
  * on that rq is picked from the hash table q->elevator->hash, which,
@@ -1881,11 +1879,6 @@ static void bfq_requests_merged(struct request_queue *q, struct request *rq,
        if (bfqq->next_rq == next)
                bfqq->next_rq = rq;
 
-       if (!RB_EMPTY_NODE(&next->rb_node)) {
-               bfq_remove_request(q, next);
-               bfqg_stats_update_io_remove(bfqq_group(bfqq), next->cmd_flags);
-       }
-
        bfqg_stats_update_io_merged(bfqq_group(bfqq), next->cmd_flags);
 }