random: fix output buffer folding
authorMatt Mackall <mpm@selenic.com>
Sat, 16 Jun 2007 17:16:11 +0000 (10:16 -0700)
committerLinus Torvalds <torvalds@woody.linux-foundation.org>
Sat, 16 Jun 2007 20:16:16 +0000 (13:16 -0700)
(As reported by linux@horizon.com)

Folding is done to minimize the theoretical possibility of systematic
weakness in the particular bits of the SHA1 hash output.  The result of
this bug is that 16 out of 80 bits are un-folded.  Without a major new
vulnerability being found in SHA1, this is harmless, but still worth
fixing.

Signed-off-by: Matt Mackall <mpm@selenic.com>
Cc: <linux@horizon.com>
Cc: Theodore Ts'o <tytso@mit.edu>
Signed-off-by: Andrew Morton <akpm@linux-foundation.org>
Signed-off-by: Linus Torvalds <torvalds@linux-foundation.org>
drivers/char/random.c

index 0474cac4a84ed882e4bb92d825beb1afcb6db69f..7f5271272f91400b17d1ac928047d5d363c35be4 100644 (file)
@@ -794,7 +794,7 @@ static void extract_buf(struct entropy_store *r, __u8 *out)
 
        buf[0] ^= buf[3];
        buf[1] ^= buf[4];
-       buf[0] ^= rol32(buf[3], 16);
+       buf[2] ^= rol32(buf[2], 16);
        memcpy(out, buf, EXTRACT_SIZE);
        memset(buf, 0, sizeof(buf));
 }