One of the more common cases of allocation size calculations is finding
the size of a structure that has a zero-sized array at the end, along
with memory for some number of elements for that array. For example:
struct foo {
int stuff;
struct boo entry[];
};
size = sizeof(struct foo) + count * sizeof(struct boo);
Instead of leaving these open-coded and prone to type mistakes, we can
now use the new struct_size() helper:
size = struct_size(instance, entry, count);
This code was detected with the help of Coccinelle.
Signed-off-by: "Gustavo A. R. Silva" <gustavo@embeddedor.com>
Tested-by: Andrew Bowers <andrewx.bowers@intel.com>
Signed-off-by: Jeff Kirsher <jeffrey.t.kirsher@intel.com>
struct i40e_qv_info *qv_info;
iavf_status err;
u32 v_idx, i;
- u32 msg_size;
+ size_t msg_size;
if (adapter->aq_required)
return -EAGAIN;
}
v_qvlist_info = (struct virtchnl_iwarp_qvlist_info *)qvlist_info;
- msg_size = sizeof(struct virtchnl_iwarp_qvlist_info) +
- (sizeof(struct virtchnl_iwarp_qv_info) *
- (v_qvlist_info->num_vectors - 1));
+ msg_size = struct_size(v_qvlist_info, qv_info,
+ v_qvlist_info->num_vectors - 1);
adapter->client_pending |= BIT(VIRTCHNL_OP_CONFIG_IWARP_IRQ_MAP);
err = iavf_aq_send_msg_to_pf(&adapter->hw,