There is an error in how the assembler version of the sc520 memory size
reporting code works. As a result, it will only ever report at most the
size of one bank of RAM
Signed-off-by: Graeme Russ <graeme.russ@gmail.com>
movl $DRCBENDADR, %edi /* DRAM ending address register */
- movl (%edi), %eax
- movl %eax, %ecx
- andl $0x80000000, %ecx
- jz bank2
- andl $0x7f000000, %eax
- shrl $2, %eax
- movl %eax, %ebx
-
-bank2: movl (%edi), %eax
+bank0: movl (%edi), %eax
movl %eax, %ecx
- andl $0x00800000, %ecx
+ andl $0x00000080, %ecx
jz bank1
- andl $0x007f0000, %eax
- shll $6, %eax
+ andl $0x0000007f, %eax
+ shll $22, %eax
movl %eax, %ebx
bank1: movl (%edi), %eax
movl %eax, %ecx
andl $0x00008000, %ecx
- jz bank0
+ jz bank2
andl $0x00007f00, %eax
shll $14, %eax
movl %eax, %ebx
-bank0: movl (%edi), %eax
+bank2: movl (%edi), %eax
movl %eax, %ecx
- andl $0x00000080, %ecx
- jz done
- andl $0x0000007f, %eax
- shll $22, %eax
+ andl $0x00800000, %ecx
+ jz bank3
+ andl $0x007f0000, %eax
+ shll $6, %eax
movl %eax, %ebx
+bank3: movl (%edi), %eax
+ movl %eax, %ecx
+ andl $0x80000000, %ecx
+ jz done
+ andl $0x7f000000, %eax
+ shrl $2, %eax
+ movl %eax, %ebx
done:
movl %ebx, %eax