SLOF has a further node which could not be evaluated
by the current routine. The current routine returns
because the node hasn't the required reg property. As
fix this patch adds a check to determine the partition
child nodes. If the node is not a partition the number
of total partitions will be decreased and loop continues
with the next nodes.
Signed-off-by: Benjamin Krill <ben@codiert.org>
Signed-off-by: David Woodhouse <David.Woodhouse@intel.com>
const u32 *reg;
int len;
+ /* check if this is a partition node */
+ partname = of_get_property(pp, "name", &len);
+ if (strcmp(partname, "partition") != 0) {
+ nr_parts--;
+ continue;
+ }
+
reg = of_get_property(pp, "reg", &len);
if (!reg || (len != 2 * sizeof(u32))) {
of_node_put(pp);