One of the more common cases of allocation size calculations is finding
the size of a structure that has a zero-sized array at the end, along
with memory for some number of elements for that array. For example:
struct foo {
int stuff;
void *entry[];
};
instance = kzalloc(sizeof(struct foo) + sizeof(void *) * count,
GFP_KERNEL);
Instead of leaving these open-coded and prone to type mistakes, we can
now use the new struct_size() helper:
instance = kzalloc(struct_size(instance, entry, count), GFP_KERNEL);
Notice that, currently, there is a bug during the allocation:
sizeof(npcm7xx_clk_data) should be sizeof(*npcm7xx_clk_data)
Fix this bug by using struct_size() in kzalloc()
This issue was detected with the help of Coccinelle.
Cc: stable@vger.kernel.org
Signed-off-by: Gustavo A. R. Silva <gustavo@embeddedor.com>
Reviewed-by: Kees Cook <keescook@chromium.org>
Reviewed-by: Avi Fishman <avifishman70@gmail.com>
Signed-off-by: Stephen Boyd <sboyd@kernel.org>
if (!clk_base)
goto npcm7xx_init_error;
- npcm7xx_clk_data = kzalloc(sizeof(*npcm7xx_clk_data->hws) *
- NPCM7XX_NUM_CLOCKS + sizeof(npcm7xx_clk_data), GFP_KERNEL);
+ npcm7xx_clk_data = kzalloc(struct_size(npcm7xx_clk_data, hws,
+ NPCM7XX_NUM_CLOCKS), GFP_KERNEL);
if (!npcm7xx_clk_data)
goto npcm7xx_init_np_err;