vsprintf: avoid misleading "(null)" for %px

Like %pK already does, print "00000000" instead.

This confused people -- the convention is that "(null)" means you tried to
dereference a null pointer as opposed to printing the address.

Link: http://lkml.kernel.org/r/20180204174521.21383-1-kilobyte@angband.pl
To: Sergey Senozhatsky <sergey.senozhatsky@gmail.com>
To: Steven Rostedt <rostedt@goodmis.org>
To: linux-kernel@vger.kernel.org
Cc: Andrew Morton <akpm@linux-foundation.org>
Cc: Joe Perches <joe@perches.com>
Cc: Kees Cook <keescook@chromium.org>
Cc: "Roberts, William C" <william.c.roberts@intel.com>
Cc: Linus Torvalds <torvalds@linux-foundation.org>
Cc: David Laight <David.Laight@ACULAB.COM>
Cc: Randy Dunlap <rdunlap@infradead.org>
Cc: Geert Uytterhoeven <geert@linux-m68k.org>
Signed-off-by: Adam Borowski <kilobyte@angband.pl>
Signed-off-by: Petr Mladek <pmladek@suse.com>

diff --git a/lib/vsprintf.c b/lib/vsprintf.c
index 77ee6ced11b17a411d95f266faeaaf7dba309d4f..d7a708f82559ca38e768cb93fc0febb999711e4c 100644 (file)
--- a/lib/vsprintf.c
+++ b/lib/vsprintf.c
@@ -1849,7 +1849,7 @@ char *pointer(const char *fmt, char *buf, char *end, void *ptr,
 {
        const int default_width = 2 * sizeof(void *);
 
-       if (!ptr && *fmt != 'K') {
+       if (!ptr && *fmt != 'K' && *fmt != 'x') {
                /*
                 * Print (null) with the same width as a pointer so it makes
                 * tabular output look nice.